Function flatten

flatten<TSource>(
src: Iterable<TSource>,
): IEnumerable<FlatIterable<Iterable<TSource>, 1>>
Returns a new IEnumerable with all sub-iterable elements concatenated into it one level deep.
Type Parameters
- TSource
Parameters
- src: Iterable<TSource>
  The source iterable.
Returns IEnumerable<FlatIterable<Iterable<TSource>, 1>>
A new IEnumerable with all sub-iterable elements concatenated into it recursively up.
Example
```
const items = [1, 2, [3, 4, [5, []]]];
const res = from(items).flatten(); // [1, 2, 3, 4, [5, []]]
```
Typeparam
TSource The type of the source iterable.
- Defined in functions/flatten.ts:16
flatten<TSource, Depth extends number>(
src: Iterable<TSource>,
depth: Depth,
): IEnumerable<FlatIterable<Iterable<TSource>, Depth>>
Returns a new IEnumerable with all sub-iterable elements concatenated into it recursively up to the specified depth.
Type Parameters
- TSource
- Depth extends number
Parameters
- src: Iterable<TSource>
  The source iterable.
- depth: Depth
  The depth to flatten to.
Returns IEnumerable<FlatIterable<Iterable<TSource>, Depth>>
A new IEnumerable with all sub-iterable elements concatenated into it recursively up.
Example
```
const items = [1, 2, [3, 4, [5, []]]];
const res = from(items).flatten(2); // [1, 2, 3, 4, 5, []]
```
Typeparam
TSource The type of the source iterable.
- Defined in functions/flatten.ts:30